Equivalence relations always create a partition of the set they are defined on, via a construction called

Question:

Equivalence relations always create a partition of the set they are defined on, via a construction called equivalence classes. For the relation in the previous problem, the equivalence classes are the pre-images. Prove directly that the collection of pre-images partition U by showing that (a) every x ∈ U is contained in some pre-image, and that (b) any two different pre-images do not have any elements in common.
Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Linear Algebra

ISBN: 9780982406212

1st Edition

Authors: Jim Hefferon

Question Posted: