Figure shows a small light bulb suspended at distance d1 = 250 cm above the surface of

Question:

Figure shows a small light bulb suspended at distance d1 = 250 cm above the surface of the water in a swimming pool where the water depth is d2 = 200 cm. The bottom of the pool is a large mirror. How far below the mirror surface is the image of the bulb? Construct a diagram of two rays like that of Figure but take into account the bending of light rays by refraction at the water surface. Assume that the rays are close to a vertical axis through the bulb, and use the small angle approximation in which sin θ ?? tan θ ?? θ.