Find the radiation resistance of the wire joining the two ends of the dipole. (This is the resistance that would give the same average power loss--to heat--as the oscillating dipole in fact puts out in the form of radiation.) Show that R = 790 (d/λ) 2 Ω, where λ is the wavelength of the radiation. For the wires in an ordinary radio (say, d = 5 cm), should you worry about the radioactive contribution to the total resistance?