Find the values of F1y and F2y required to give a net torque of 0.0099 N ∙ m. This is a torque that would be effective at rotating the tooth.

A. F1y = -1.7 N, F2y = 3.5 N

B. F1y = -3.8 N, F2y = 5.6 N

C. F1y = -0.23 N, F2y = 2.0 N

D. F1y = 4.0 N, F2y = -2.2 N

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Canine F2 - First premolar Second premolar (a) 3 Net force of 1.8 N 2 FO0O- 0.004 0.006 0.002 0.008 0.010 Torque (N• m) -1 II (b) y component of force (N)