Question: For Prob. 1218 a satisfactory design is d = 2.000+0 in b = 2.005+0.003 in 0.001 -0 Double the size of the bearing dimensions and
For Prob. 12–18 a satisfactory design is
d = 2.000+0 in b = 2.005+0.003 in
−0.001 -0
Double the size of the bearing dimensions and quadruple the load to 3600 lbf.
(a) Analyze the scaled-up bearing for median assembly.
(b) Compare the results of a similar analysis for the 2-in bearing, median assembly.
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Originally Doubled d 20000000 0001 in b 20050003 0000 in d 40000002 in ... View full answer
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