Question: If the exponent of e of a bivariate normal density is 1/54 (x2 + 4y2 + 2xy+ 2x+ 8y+ 4) Find 1, 2, and ,

If the exponent of e of a bivariate normal density is
–1/54 (x2 + 4y2 + 2xy+ 2x+ 8y+ 4)
Find σ1, σ2, and ρ, given that µ1 = 0 and µ2 = –1.

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