In each case, find P = P = B† B and verify that P-1MB0(T)P = MB(T) for the given operator T.
(a) T :R3 †’R3, T(a, b, r) = (2a -b ,b + c, c - 3a); B0 = {(1, 1,0), (1,0, 1), (0, 1,0)} and B is the standard basis.
(b) T: P2 † P2,
T(a + bx + cx2) = (a + b) + (b + c)x + (r + a)x2; B0 = {1, x, x2} and B = {1 - x, x2, 1 + x, 2x + x2}:
(c) T:M22 †’ M22,

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