In Figure a, string 1 has a linear density of 3.00g/m, and string 2 has a linear
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In Figure a, string 1 has a linear density of 3.00g/m, and string 2 has a linear density of 5.00g/m. They are under tension due to the hanging block of mass M = 500 g Calculate the wave speed on(a) String 1 and(b) String 2.Next the block is divided into two blocks (with M1 t Mz - M) and the apparatus is rearranged as shown in Figure b. Find(c) M1 and(d) M2 such that the wave speeds in the two strings are equal.
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String 1 String 2 Knot м (a) String 1 String 2 M2 м (b)
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a The tension in each string is given by t Mg2 Thus the wave speed in ...View the full answer
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Related Book For
Fundamentals of Physics
ISBN: 978-0471758013
8th Extended edition
Authors: Jearl Walker, Halliday Resnick
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