Question: In our first look at the ideal gas we considered only the translational energy of the particles. But molecules can rotate, with kinetic energy. The
In our first look at the ideal gas we considered only the translational energy of the particles. But molecules can rotate, with kinetic energy. The rotational motion is quantized: and the energy levels of a diatomic molecule are of the form
ε(j) = j(j + 1)ε0
Where j is any positive integer including zero; j = 0, 1, 2 . . . The multiplicity of each rotational level is g(j) = 2j + 1.
(a) Find the partition function ZR(τ) for the rotational states of one molecule. Remember that Z is a slim over all stales, not over all levels–this makes a difference.
(b) Evaluate ZR(τ) approximately for τ >> ε0, by converting the sum to an integral
(c) Do the same for τ << ε0, by truncating the sum after the second term
(d) Give expressions for the energy U and the heat capacity C, as functions of τ, in the both limits. Observe that the rotational contribution to the heat capacity of a diatomic molecule approaches 1 (or, in conventional units, ku) when r >> ε0.
(e) Sketch the behavior of U(τ) and C(τ) showing the limiting behaviors for τ → ∞ and τ → 0.
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a There are 2j1 states at energy jj1 0 hence Where the sum over all states has been converted into a sum over all energy levels b The sum may be viewed as a sum over the areas of rectangles with the w... View full answer
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