In the Deacon process for the manufacture of chlorine, HC 1 and O 2 react to form Cl 2 and H 2 0 Sufficient air (21 mole 0 2 , 79 N 2 ) is fed to provide 35 excess oxygen and the fractional conversion of HCI is 85 (a) Calculate the mole fractions of the product stream components using atomic specie...

a 2HC120 Cl HO 100 mol HC1 n mol air 021 mol Omol 079 mol N mol 35 excess Basis 100 mol HC1 fed to r ...

In the Deacon process for the manufacture of chlorine, HC 1 and O 2 react to form

Question:

In the Deacon process for the manufacture of chlorine, HC₁ and O₂ react to form Cl₂ and H₂0. Sufficient air (21 mole% 0₂, 79% N₂) is fed to provide 35% excess oxygen and the fractional conversion of HCI is 85%.

(a) Calculate the mole fractions of the product stream components using atomic species balances in your calculation.

(b) Again calculate the mole fractions of the product stream components, only this time use the extent of reaction in the calculation.

(c) An alternative to using air as the oxygen source would be to feed pure oxygen to the reactor. Running with oxygen imposes a significant extra process cost relative to running with air, but also offers the potential for considerable savings. Speculate on what the cost and savings might be. What would determine which way the process should be run?