In the first network that we analyzed, with the three resistors in series, we just added to get that they acted together like a single resistor of 10 ohms. We can do a similar thing for parallel circuits. In the second circuit analyzed,

the electric current through the battery is 25/6 amperes. Thus, the parallel portion is equivalent to a single resistor of 20/(25/6) = 4:8 ohms.
(a) What is the equivalent resistance if we change the 12 ohm resistor to 5 ohms?
(b) What is the equivalent resistance if the two are each 8 ohms?
(c) Find the formula for the equivalent resistance if the two resistors in parallel are r1 ohms and r2 ohms.

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20 volt 12 ohm 8 ohm