Inductors in Series BDd Parallel. You arc given two inductors, one of self-inductance L. and the other

Question:

Inductors in Series BDd Parallel. You arc given two inductors, one of self-inductance L. and the other of self-inductance L2.
(a) You connect the two inductors in series and arrange them so that their mutual inductance is negligible. Show that the equivalent inductance of the combination is Leq = L1 + L2.
(b) You now conneet the two inductors in parallel. again arranging them so that their mutual inductance is negligible. Show that the equivalent inductance of the combination is Leq = (1/L1 + 1/L2)-1.
Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Fundamentals Of Electric Circuits

ISBN: 9780073301150

3rd Edition

Authors: Matthew Sadiku, Charles Alexander

Question Posted: