Inductors in Series BDd Parallel. You arc given two inductors, one of self-inductance L. and the other
Question:
(a) You connect the two inductors in series and arrange them so that their mutual inductance is negligible. Show that the equivalent inductance of the combination is Leq = L1 + L2.
(b) You now conneet the two inductors in parallel. again arranging them so that their mutual inductance is negligible. Show that the equivalent inductance of the combination is Leq = (1/L1 + 1/L2)-1.
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Related Book For
Fundamentals Of Electric Circuits
ISBN: 9780073301150
3rd Edition
Authors: Matthew Sadiku, Charles Alexander
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