Let f be C1 and suppose that Df[x0] is one-to-one. Then 1. f is locally one-to-one, that

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Let f be C1 and suppose that Df[x0] is one-to-one. Then
1. f is locally one-to-one, that is, there exists a neighborhood S of x0 such that f is one-to-one on S
2. f has an inverse f-1: f(S) → S that is continuous
3. f is locally onto
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