Question: Linear ionic crystal Consider a line of 2N ions of alternating charge q with a repulsive potential energy A/R n between nearest neighbors. (a)

Linear ionic crystal Consider a line of 2N ions of alternating charge ± q with a repulsive potential energy A/Rn between nearest neighbors. 

(a) Show that at the equilibrium separation (CGS) U (R0) = – 2NqIn2/R0(1 – 1/n).

(b) Let the crystal be compressed so that R0 → R0(l – δ). Show that the work done in compressing a unit length of the crystal has the leading term 1/2Cδ2, where (CGS) C = (n – 1) q2 In2/R0. To obtain the results in SI, replace q2 by q2/4πε0. Note: We should not expect to obtain this result from the expression for U (R0), but we must use the complete expression for U(R).

Step by Step Solution

3.49 Rating (179 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a In equilibrium and UR N au OR A R N aq R nA a 2 log 2 Madel... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

14-P-S-S-G-P (15).docx

120 KBs Word File

Students Have Also Explored These Related Solid State Questions!