Question: Liquid n-pentane at 25C is burned with 30% excess oxygen (not air) fed at 75C. The adiabatic flame temperature is T ad (C). (a) Take
Liquid n-pentane at 25°C is burned with 30% excess oxygen (not air) fed at 75°C. The adiabatic flame temperature is Tad (°C).
(a) Take as a basis of calculation 1.00 mol C5H12 (l) burned and use an energy balance on the adiabatic reactor to derive an equation of the form f(Tad) = 0 where f(Tad) is a fourth-order polynomial [f (Tad) = C0 + C1 Tad + C2T2ad + C3T3ad + c4T4ad]. If your derivation is correct, the ratio c0, c4 should equal – 6.892 x 1014. Then solve the equation to determine Tad. (This solution is easily obtained using the goal seek tool on a spreadsheet.)
(b) Repeat the calculation of part (a) using successively the first two terms, the first three terms, and the first four terms of the fourth-order polynomial equation. If the solution of part (a) is taken to be exact, what percentage errors are associated with the linear (two-term), quadratic (three-term), and cubic (four-term) approximations?
(c) Determine the fourth-order solution using Newton’s method (Appendix A.2) taking the linear approximation as the first guess and stopping when |f (Tad)| <0.01.
(d) Why is the fourth-order solution at best an approximation and quite possibly a poor one?
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a Basis 1 mol CsH12 1 C5H2 1 80g 5COg 6HOv AH35095 kJmol 1 mol CsH12 1 no mol O 75C 30 excess Theore... View full answer
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