Question: Solve the system by the method of substitution. 1. 2. 3. Jx + y = 2 lx y = 0 /2x %3D 3 %3D0

Solve the system by the method of substitution.
1.

Jx + y = 2 lx – y = 0

2.

/2x — Зу %3D 3 х — у%3D0 У

3.

Jx + y = 2 lx y = 0 /2x %3D 3

Jx + y = 2 lx y = 0 /2x %3D 3 %3D0

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