Referring to Example 25.12, show that the map : Z[2] R where (m + n2) =
Question:
Referring to Example 25.12, show that the map ∅: Z[√2] → R where ∅(m + n√2) = m - n√2 is a homomorphism.
Data from Example 25.12
Exercise 11 of Section 18 shows that {m + n√2| m, n ∈ Z} is a ring. Let us denote this ring by Z[√2]. This ring has a natural order induced from R. in which √2 is positive. However, we claim that ∅: Z[√2] → Z[√2] defined by ∅(m + n√2) = m - n√2 is an automorphism. It is clearly one to one and onto Z[√2]. We leave the verification of the homomorphism property to Exercise 17. Because ∅(√2) = -√2, we see the ordering induced by ∅ will be one where -√2 is positive! In the natural order on Z[√2], an element m + n√2 is positive if m and n are both positive, or if m is positive and 2n2 < m2 , or if n is positive and m2 < 2n2. In Exercise 3, we ask you to give the analogous descriptions for positive elements in the ordering of Z[√2] induced by ∅.
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