Exercise 5.6.2 Argue that [ 1+ f (a, a +b+c) ]b+c = [ 1+ f (a, a

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Exercise 5.6.2 Argue that [ 1+ f

(a, a +b+c) ]b+c = [ 1+ f

(a, a +b) ]b[ 1+ f (a +

b, a +b+c) ]c.

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