Question: Solve by the Laplace transform, showing the details and graphing the solution: y' 1 = y 2 + u(t - ), y' 2 = -y
Solve by the Laplace transform, showing the details and graphing the solution:
y'1 = y2 + u(t - π), y'2 = -y1 + u(t - 2π), y1(0) = 1, y2(0) = 0
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y1t A sin2t B cos 2t 2 y2t Acos 2t Bsin 2t where Acos and Bsin are the first two antideriva... View full answer
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