Question: Solve by the Laplace transform, showing the details and graphing the solution: y - y' - 2y = 12u(t - ) sin t, y(0) =

Solve by the Laplace transform, showing the details and graphing the solution:

y" - y' - 2y = 12u(t - π) sin t, y(0) = 1, y' (0) = -1

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