What happens in Prob. 2 if you replace y(2) = 1 with y(2) = k? Data from
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What happens in Prob. 2 if you replace y(2) = 1 with y(2) = k?
Data from prob 2.
Does the initial value problem (x - 2)y' = y, y(2) = 1 have a solution? Does your result contradict our present theorems?
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For k 0 we still get no solution violating the ex...View the full answer
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