An electric cell is based on the reaction (mathrm{Pb}+mathrm{Hg}_{2} mathrm{Cl}_{2} ightarrow mathrm{PbCl}_{2}+2 mathrm{Hg}). If the enthalpy

An electric cell is based on the reaction \(\mathrm{Pb}+\mathrm{Hg}_{2} \mathrm{Cl}_{2} \rightarrow \mathrm{PbCl}_{2}+2 \mathrm{Hg}\). If the enthalpy of reaction for this reaction, \(Q_{p}\), at \(25^{\circ} \mathrm{C}\) is \(-95,200 \mathrm{~kJ} / \mathrm{kg} \mathrm{Pb}\), calculate the emf, and rate of change of emf with temperature at constant pressure if the heat transfer to the cell is \(8300 \mathrm{~kJ} / \mathrm{kg} \mathrm{Pb}\).

\(\left[0.5363 \mathrm{~V} ; 1.44 \times 10^{-4} \mathrm{~V} / \mathrm{K}\right]\)