Select a long-throated flume from Table 14.5 that will carry a range of flow from 30 gal/min to 500 gal/min. Compute the head for each of these flows and then compute the flow that would result from four additional heads spaced approximately equally between them.

TABLE 14.5 Long-throated flume data Design A Design B Design C Rectangular channels: Q = b.Ki(H + K2" 0.500 ft 1.000 t 1.500 ft 0.750 ft 1.000 ft 2.250 ft 0.125 ft Pi 0.250 ft 0.500 ft 3.996 K 3.696 3.375 0,000 0.004 0.011 1.612 1.617 1.625 Hmin 0.057 ft Hmn 0.082 t Hnin 0.148 ft Hma 0.462 ft 0.701 t Hmar 1.500 ft P1 Qmn 0.020 f/s Qmn 0.070 s Qmn 0.255 s Qman 0.575 ft's Qmar 2.100 tis Qmar 9.900 ft's Trapezoidal channels: Q = K;(H + K2" 1.000 ft 1.000 ft 2.000 ft 2.000 ft 4.000 ft 5.000 ft 0.750 ft 1.000 ft 1.000 ft 0.500 ft 1.500 ft 1.500 ft 9.290 14.510 16.180 0.030 K2 0.053 0.035 1.878 1.855 1.784 Hmin 0.400 ft Hmin 0.579 ft Hmin 0.580 ft Hmar 0.893 ft Hmex 0.808 t 1.456 ft Qmn 1.900 ft/s Qmn 6.200 fs Qmn 6.800 ts Qma 8.000 f/s 11.000 As Qma 33.000 fts Circular channels: Q = DK,(H/D + K" D 1.000 ft 2.000 t D 3.000 ft. be 0.866 ft 1.834 t 2.940 ft 0.600 ft 1.100 ft 1.350 ft 0.750 ft 1.800 ft 3.600 ft 1.125 ft 2.100 ft 2.700 ft P1 0.250 ft 0.600 t 1.200 ft 3.970 3.780 3.507 0.004 0.000 0.000 1.689 1.625 1.573 Hmin 0.069 ft 0.140 t Hmin 0.180 ft Hma 0.599 ft Hma 1.102 t Hmar 1.343 ft P1 Qmn 0.048 ft/s Qmn 0.283 ts Qmn 0.655 fs Qma 1.689 ft's Qmar 8.112 t/s Qmar 15.448 f/s