If a rocket is launched with an initial velocity of 320 ft/s, its height above ground after
Question:
If a rocket is launched with an initial velocity of 320 ft/s, its height above ground after t seconds is given by −16t2 + 320t (in ft). Find the times when the height is 0.
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Step by Step Answer:
To find the times when the height of the rocket is 0 we need to solve the equation 16t2 320t 0 ...View the full answer
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Related Book For 
Basic Technical Mathematics
ISBN: 9780137529896
12th Edition
Authors: Allyn J. Washington, Richard Evans
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