Make the given changes in the indicated examples of this section and then find the indicated values.

In Example 3, in line 2, change 2.000 min to 3.000 min and then find the altitude.

Data from Example 3

A missile is launched at an angle of 26.55° with respect to the horizontal. If it travels in a straight line over level terrain for 2.000 min and its average speed is 6355 km/h, what is its altitude at this time?

In Fig. 4.41, we let h represent the altitude of the missile after 2.000 min (altitude is measured on a perpendicular line). Also, we determine that in this time the missile has flown 211.8 km in a direct line from the launching site. This is found from the fact that it travels at 6355 km/h for 1/30.00 h (2.000min) and distance = speed × time. We therefore have

This means

Transcribed Image Text:

1 (6355 km)(30.00 h = 211.8 km.