Don’t sweat the small stuff. Consider a study in which 40 of 320 individuals (12.5%) in the treatment group experience an outcome.

In contrast, 26 of 336 (7.7%) of the individuals in the control group experience the outcome. Table 18.28 displays the data in crosstabulated form. Calculate chi-square statistics and P-values for this problem using both the Pearson’s and continuity-corrected (Yates’)

chi-square statistics. (If your instructor allows, consider using a software program such as WinPepi’s Compare2.exe program to calculate results.) Interpret the results of the tests. Is it reasonable to derive different conclusions from these different test statistics?
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