Factor each of the following expressions, in which both the coefficient of the x term and the constant term are now negative.

(a) x2 − 8x − 48 With (c ·

d) and (c +

d) both negative, the factors must be of different signs and the factor with the larger absolute value must be negative.

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(1) c.d=-48 (2) c+d-8. [1,-48; 2,-24; 3, -16; 4, -12; 6, -8] (b) x-26x-56 (1) c d -56 = (2) c+d=-26 [4+(-12)=-8] x28x48=(x+4)(x - 12) [1,-56; 2,-28; 4, -14; 7, -8] [2+(-28)=-26] x-26x-56 = (x+2)(x-28)