Given the polynomial mx2 + nx + p, show that the factors are (ax + c)(bx +

d) where ab = m, ad + bc

= n, and cd = p.

By reversing the process of multiplication, we can express the polynomial

Carrying out the multiplication on the right-hand side,

From (1.1) it is evident that ab = m, ad + bc = n, and cd = p.

Transcribed Image Text:

mx+nx + p = (ax+c)(bx+d)