The average number of broken eggs per lorry is known to be 50. What is the probability that there will be more than 70 broken eggs on a particular lorry load?

We may use the normal approximation to the Poisson distribution, where the mean and variance are calculated as follows: mean (μNormal ≈ μPoisson = λ = 50) and variance

Require P(X > 70 for Poisson) ≈ P(X > 70.5 for normal).

The area shaded in Figure 4.42 is an approximation of the probability of obtaining more than 70 broken eggs.

We can see that the Poisson probability distribution solution, P(X > 70) _Poisson ≈ P (X ≥ 70.5) _normal.

Transcribed Image Text:

(Normal = 0 Poisson = = λ = 50).