If x and y are real numbers with y 0 and y(y + 1) (x
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If x and y are real numbers with y ≥ 0 and y(y + 1) ≤ (x + 1)², then y(y − 1) ≤ x².
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To prove this statement we can subtract x 1 from both sides of yy 1 x 1 yy 1 x ...View the full answer
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