In Exercises determine whether the series converges absolutely or conditionally, or diverges. n=1 sin[(2n-1)/2] n

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In Exercises determine whether the series converges absolutely or conditionally, or diverges.

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Calculus

ISBN: 9781285057095

10th Edition

Authors: Ron Larson, Bruce H. Edwards

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Question Posted: Mar 13, 2023 02:34 AM

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In Exercises determine whether the series converges absolutely or conditionally, or diverges. n=1 sin[(2n-1)/2] n

Question:

n=1 sin[(2n-1)π/2] n

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sin2n 172 1 n n The given serie...View the full answer

Calculus

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