The segment BD is the height of OAB. Let R be the ratio of the area of
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The segment BD is the height of ΔOAB. Let R be the ratio of the area of ΔDAB to that of the shaded region formed by deleting ΔOAB from the circular sector subtended by angle 0 (see figure). Find 
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sin BD cos 0 OD Area ADAB DABD 2 Shaded area R lim R 00 1 1...View the full answer
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