A narrow, negatively charged ring of radius R exerts a force on a positively charged particle P

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A narrow, negatively charged ring of radius R exerts a force on a positively charged particle P located at distance x above the center of the ring of magnitude

F(x)= kx (x + R)/2

where k > 0 is a constant (Figure 10).

(a) Compute the third-degree Maclaurin polynomial for F.
(b) Show that F ≈ −(k/R3)x to second order. This shows that when x is small, F(x) behaves like a restoring force similar to the force exerted by a spring.
(c) Show that F(x) ≈ −k/x2 when x is large by showing that

F(x) lim X-00 -k/x = 1

Thus, F(x) behaves like an inverse square law, and the charged ring looks like a point charge from far away.

Ju P R. F(x) Nearly linear here Nearly inverse square here X

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Calculus

ISBN: 9781319055844

4th Edition

Authors: Jon Rogawski, Colin Adams, Robert Franzosa

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