A right circular cone (Figure 18) has volume V = /3 r 2 h and surface area
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A right circular cone (Figure 18) has volume V = π/3 r2 h and surface area S = πr √r2 + h2. Find the dimensions of the cone with surface area 1 and maximal volume.
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We have r r h 1 sorr h 1 and hence h 1 and now we must maximize V h xx 31 where 0 r 1 ...View the full answer
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