Find the extreme values of (x, y, z) = x + 2y + 3z subject to the

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Find the extreme values of ƒ(x, y, z) = x + 2y + 3z subject to the two constraints x + y + z = 1 and x2 + y2 + z2 = 1.

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Calculus

ISBN: 9781319055844

4th Edition

Authors: Jon Rogawski, Colin Adams, Robert Franzosa

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