A car rolls down a hill. Its distance (in feet) from its starting point is given by
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A car rolls down a hill. Its distance (in feet) from its starting point is given by s(t) = 1.5t2 + 4t, where t is in seconds.
(a) How far will the car move in 10 seconds?
(b) What is the velocity at 5 seconds? At 10 seconds?
(c) How can you tell from v(t) that the car will not stop?
(d) What is the acceleration at 5 seconds? At 10 seconds?
(e) What is happening to the velocity and the acceleration as t increases?
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st 15t 2 4t a The car will move 190 ft in 10 seconds b vt st 3t 4 The velocity ...View the full answer
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