If a cannonball is shot directly upward with a velocity of 256 ft per second, its height
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If a cannonball is shot directly upward with a velocity of 256 ft per second, its height above the ground after t seconds is given by s(t) = 256t - 16t2. Find the velocity and the acceleration after t seconds. What is the maximum height the cannonball reaches? When does it hit the ground?
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