a Given that 3sec 4 cosec 2 cosec 2, show that 3sin 4 cos 1 b Express 3sin 4 cos in the form Rsin( ) , where R 0 and 0 90 Give the value of correct to 2 decimal places c Hence solve the equation 3sec 4 cosec 2 cosec 2 for 0 360 ...

a We are given 3sec 4cosec 2cosec 2 We can write cosec 2 as 2cosec cos 3sec 4cosec 22cosec cos Divid ...

a. Given that 3sec + 4 cosec = 2 cosec 2, show that 3sin +

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a. Given that 3sec θ + 4 cosec θ = 2 cosec 2θ, show that 3sinθ + 4 cosθ = 1.

b. Express 3sinθ + 4 cosθ in the form Rsin(θ + α) , where R > 0 and 0°< α < 90°.

Give the value of α correct to 2 decimal places.
c. Hence solve the equation 3secθ + 4 cosecθ = 2 cosec 2θ for 0°< θ < 360°.

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Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook

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Authors: Sue Pemberton, Julianne Hughes, Julian Gilbey

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a. Given that 3sec + 4 cosec = 2 cosec 2, show that 3sin +

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a We are given 3sec 4cosec 2cosec 2 We can write cosec 2 as 2cosec cos 3sec 4cosec 22cosec cos Divid...View the full answer

Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook

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