Solve. a. log 10 (2x + 9) - log 10 5 = 1 b. log 3 2x

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Solve.

a. log10 (2x +  9) - log10 5 = 1

b. log3 2x - log3 (x - 1) = 2

c. log2 (5 - 2x) = 3 +  log2 (x + 1)

d. log5 (2x - 3) + 2log5 2 = 1+log(3 - 2x)

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