Solve each equation for 0 < < 360. a. 2 sin2 = cos b. 2 cos2
Question:
Solve each equation for 0° < θ < 360°.
a. 2 sin2θ = cosθ
b. 2 cos2θ + 3 = 4 cosθ
c. 2 cos 2θ + 1 = sinθ
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a 2 sin2 cos Using the double angle formula for sine we have 22sin cos cos 4sin cos cos 0 cos4sin 1 ...View the full answer
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Related Book For
Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook
ISBN: 9781108407199
1st Edition
Authors: Sue Pemberton, Julianne Hughes, Julian Gilbey
Question Posted:
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