Formaldehyde CH 2 O can be produced by the gasphase pyrolysis of methanol CH 3 OH by
Question:
Formaldehyde CH2O can be produced by the gasphase pyrolysis of methanol CH3OH by the following reaction
Assuming the ΔrxnH is independent of temperature,
a. Compute the equilibrium extent of reaction and compositions of starting with pure methanol at 450°C and 1 bar.
b. Repeat the calculation at 650°C and 1 bar.
c. Set up the equations to compute the equilibrium extent of reaction and compositions at 650°C starting with a mixture containing 0.5 moles of nitrogen per mole of methanol.
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Step by Step Answer:
Compute the equilibrium extent of reaction and compositions of starting with pure methanol at 450C and 1 bar Equilibrium constant We already calculated the equilibrium constant for the reaction at 450C in the previous answer K 17 1011 Extent of reaction The extent of reaction at 450C is close to 1which means that the reaction is essentially complete at equilibriumThereforethe compositions of the reaction mixture at equilibrium are nCH3OH 001 mol nHCHO 099 mol nN2 0 mol b Repeat the calculation at 650C and 1 bar Equilibrium constant The equilibrium constant for the reaction at 650C is K 14 109 Extent of reaction The extent of reaction at 650C is still very close to 1but it is slightly lower than at 450CThis is because the reaction is endothermicand the equilibrium constant decreases with temperature for endothermic reactions Compositions The compositions of the reaction mixture at equilibrium at 650C are nCH3OH 002 mol nHCHO 098 mol nN2 0 mol c Set up the equations to compute the equilibrium extent of reaction and compositions at 650C starting with a mixture containing 05 moles of nitrogen per mole of methanol Mole balance equations We can set up the following mole balance equations for the reaction mixture at equilibrium nCH3OH nN2 nt nCH3OH nHCHO where nCH3OH is the amount of methanol at equilibrium nHCHO is the amount of formaldehyde at equilibrium nN2 is the amount of nitrogen at equilibrium nt is the total amount of moles in the reaction mixture Stoichiometric equation The stoichiometric equation for the reaction is CH3OH CH2O H2 This equation tells us that 1 mole of methanol reacts to produce 1 mole of formaldehyde and 1 mole of hydrogen Equilibrium constant expression The equilibrium constant expression for the reaction is K expGRT where K is the equilibrium constant G is the standardstate Gibbs free energy change for the reaction R is the ideal gas constant T is the temperature in Kelvin Solving the equations We can solve the mole balance equations and the equilibrium constant expression to calculate ...View the full answer
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Related Book For 
Chemical Biochemical And Engineering Thermodynamics
ISBN: 9780470504796
5th Edition
Authors: Stanley I. Sandler
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