The feed to a pentane isomerization process consists of (650 mathrm{kmol} / mathrm{hr}) of n-pentane and (300

Question:

The feed to a pentane isomerization process consists of \(650 \mathrm{kmol} / \mathrm{hr}\) of n-pentane and \(300 \mathrm{kmol} / \mathrm{hr}\) of isopentane. The effluent from the catalytic isomerization reactor will contain 6.5 moles of isopentane for every mole of n-pentane. The catalyst prevents the formation of neopentane. If the isopentane product, produced by separating isopentane from n-pentane by distillation, is to contain only \(2 \mathrm{wt} \%\) n-pentane and the separation system is to be placed before the reactor, calculate the total flow rate and composition of the reactor effluent, the combined feed to the reactor, and the bottoms product from the distillation column. Design the distillation column. Repeat the material balance calculations and the design of the distillation column if the separation system is placed after the reactor. Based on your results and without determining any capital or operating costs, which separation system placement is preferred?

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Product And Process Design Principles Synthesis Analysis And Evaluation

ISBN: 9781119355243

4th Edition

Authors: Warren D. Seider, Daniel R. Lewin, J. D. Seader, Soemantri Widagdo, Rafiqul Gani, Ka Ming Ng

Question Posted: