Consider (100.0 mathrm{~mL}) of a (0.100 mathrm{M}) solution of (mathrm{H}_{3}mathrm{~A}) (left(K_{mathrm{a}_{1}}=1.5 times 10^{-4}, K_{mathrm{a}_{2}}=3.0 times 10^{-8}, K_{mathrm{a}_{3}}=5.0
Question:
Consider \(100.0 \mathrm{~mL}\) of a \(0.100 \mathrm{M}\) solution of \(\mathrm{H}_{3}\mathrm{~A}\) \(\left(K_{\mathrm{a}_{1}}=1.5 \times 10^{-4}, K_{\mathrm{a}_{2}}=3.0 \times 10^{-8}, K_{\mathrm{a}_{3}}=5.0 \times 10^{-12}ight)\).
a. Calculate the \(\mathrm{pH}\) of this solution.
b. Calculate the \(\mathrm{pH}\) of the solution after \(10.0 \mathrm{~mL}\) of \(1.00 \mathrm{M} \mathrm{NaOH}\) has been added to the original solution.
c. Calculate the \(\mathrm{pH}\) of the solution after \(25.0 \mathrm{~mL}\) of \(1.00 \mathrm{M} \mathrm{NaOH}\) has been added to the original solution.
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: