In a coffee-cup calorimeter, 150.0 mL of 0.50 M HCl is added to 50.0 mL of 1.00
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In a coffee-cup calorimeter, 150.0 mL of 0.50 M HCl is added to 50.0 mL of 1.00 M NaOH to make 200.0 g solution at an initial temperature of 48.28C. If the enthalpy of neutralization for the reaction between a strong acid and a strong base is -56 kJ/mol, calculate the final temperature of the calorimeter contents. Assume the specific heat capacity of the solution is 4.184 J C-1 g-1 and assume no heat loss to the surroundings.
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Calculation The enthalpy change for the reaction is q ...View the full answer
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Labindao Antoque
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