The production of a product P from a particular gram-negative bacteria follows the Monod growth law rg=maxCsCcKS+Cs
Question:
The production of a product P from a particular gram-negative bacteria follows the Monod growth law
rg=μmaxCsCcKS+Cs
with μmax = 1 h–1, KS = 0.25 g/dm3, and Yc/s = 0.5 g/g.
a. The reaction is to be carried out in a batch reactor with the initial cell concentration of Cc0 = 0.1 g/dm3 and substrate concentration of Cs0 = 20 g/dm3.
b. The reaction is now to be carried out in a CSTR with Cs0 = 20 g/dm3 and Cc0 = 0. What is the dilution rate at which washout occurs?
c. For the conditions in part (b), what is the dilution rate that will give the maximum product rate (g/h) if Yp/c = 0.15 g/g? What are the concentrations Cc, Cs, Cp, and
–rs at this value of D?
d. How would your answers to (b) and (c) change if cell death could not be neglected with kd = 0.02 h–1?
e. How would your answers to (b) and (c) change if maintenance could not be neglected with m = 0.2 g/h/dm3?
f. Redo part (a) and use a logistic growth law
rg=μmax(1−CcC∞)Cc
and plot Cc and rc as a function of time. The term C∞ is the maximum cell mass concentration and is called the carrying capacity, and is equal to C∞ = 1.0 g/dm3. Can you find an analytical solution for the batch reactor? Compare with part (a) for C∞ = Yc/s Cs0 + Cc0.
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