The reaction A + B 2C takes place in an unsteady CSTR. The feed is only
Question:
The reaction A + B → 2C takes place in an unsteady CSTR. The feed is only A and B in equimolar proportions. Which of the following sets of equations gives the correct set of mole balances on A, B, and C? Species A and B are disappearing and species C is being formed. Circle the correct answer where all the mole balances are correct. (a) (b)
1. FB0−FA−∫VrAdV=dNAdtFB0−FB−∫VrAdV=dNBdt−FC+2∫VrAdV=dNCdt
2. FA0−FA+∫VrAdV=dNAdtFA0−FB+∫VrAdV=dNBdt−FC–2∫VrAdV=dNCdt
3. FA0−FA+∫V0rAdV=dNAdtFA0−FB+∫VrAdV=dNBdt−FC+∫VrCdV=dNCdt
4. FB0−FA−∫VrAdV=dNAdtFB0−FA0−∫VrAdV=dNBdt−FC+∫VrCdV=dNCdt
5. None of the above.
This problem was written in honor of Ann Arbor, Michigan’s own Grammy winning artist, Bob Seger (https://www.youtube.com/channel/UComKJVf5rNLl_RfC_rbt7qg/videos).
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