A 0.5224-g sample of an unknown monoprotic acid was titrated with 0.0998 M NaOH. The equivalence point

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A 0.5224-g sample of an unknown monoprotic acid was titrated with 0.0998 M NaOH. The equivalence point of the titration occurred at 23.82 mL. Determine the molar mass of the unknown acid.

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Chemistry A Molecular Approach

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Authors: Nivaldo Tro

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Question Posted: Nov 24, 2023 01:21 AM

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A 0.5224-g sample of an unknown monoprotic acid was titrated with 0.0998 M NaOH. The equivalence point

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Step 1 Calculate the moles of NaOH used moles of N...View the full answer

Chemistry A Molecular Approach

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