Consider the reaction:

A reaction mixture at equilibrium at 175 K contains P_H2 = 0.958 atm, P_I2 = 0.877 atm, and P_HI = 0.020 atm. A second reaction mixture, also at 175 K, contains P_H2 = P_I2 = 0.621 atm and P_HI = 0.101 atm. Is the second reaction at equilibrium? If not, what will be the partial pressure of HI when the reaction reaches equilibrium at 175 K?

Transcribed Image Text:

H₂(g) + 1₂(g) = 2 HI(g)