Radon-220 undergoes alpha decay with a half-life of 55.6 s. Assume there are 16,000 atoms present initially
Question:
Radon-220 undergoes alpha decay with a half-life of 55.6 s.
Assume there are 16,000 atoms present initially and make a table showing how many atoms will be present at 0 s, 55.6 s, 111.2 s, 166.8 s, 222.4 s, and 278.0 s (all multiples of the half-life). Now calculate how many atoms will be present at 50 s, 100 s, and 200 s (not multiples of the half-life). Make a graph with number of atoms present on the y-axis and total time on the x-axis.
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: