The Hg 2+ ion forms complex ions with I - as follows: A solution is prepared by

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The Hg2+ ion forms complex ions with I- as follows:

Hg+ (aq) + I (aq) = HgI+ (aq) + (aq) = (aq): Hgl(aq) + Hgl, (aq) + (aq)  = HgI*(aq) Hgl(aq) Hgl, (aq) HgI

A solution is prepared by dissolving 0.088 mole of Hg(NO3)2 and 5.00 moles of NaI in enough water to make 1.0 L of solution.  

a. Calculate the equilibrium concentration of [HgI4]. b. Calculate the equilibrium concentration of [I]. c.

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Chemistry An Atoms First Approach

ISBN: 9781305079243

2nd Edition

Authors: Steven S. Zumdahl, Susan A. Zumdahl

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